After completing this section, you should be able to write structural formulas for all the unknown compounds described in this problem. Try to do so before viewing the answers.
Deducing the structure of H is the key to solving this problem. From its formula H is clearly an alkane. There are three possible constitutional isomers having this formula. They are pentane, CH3(CH2)3CH3, 2-methylbutane, (CH3)2CHCH2CH3, and 2,2-dimethylpropane, (CH3)4C. For each of these carbon frameworks (skeletons) the number of possible alcohol derivatives is different, as noted in the following table.
| Parent Alkane | Derived Alcohols |
| pentane | three (chain locations 1, 2 & 3) |
| 2-methylbutane | 4 (chain locations 1, 2, 3 & 4) |
| 2,2-dimethylpropane | one (chain location 1) |
The assignment of structural formulas to B and C is straightforward, since B does not react with PCC and is therefore a 3¡-alcohol (only one is possible) and C reacts to give a ketone (K) and is therefore a 2¡-alcohol. To distinguish the 1¡-alcohols A and D, both of which react with PCC to give isomeric aldehydes (M & N), it is necessary to consider the alkenes produced by dehydration with hot phosphoric acid. A gives an alkene E, which is also one of the alkenes produced by dehydration of B. Likewise D gives an alkene G, which is one of the alkenes produced by dehydration of C. This relationship permits an unambiguous assignment of structure to these alcohols.